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Probability of obtaining genotype AABbcc in cross between AaBbCc ^ AaBbcc is (1)1/16 (2)1/8 (3)1/32 (4)1/64 Plz give the formula and explanation |
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Answer» The correct ANSWER is the last choice, 1/64Explanation:The PROBABILITY of producing the homozygote AABBCC is 1/64, assuming that Mendel's law of segregation is true. The probability of generating a homozygote recessive INDIVIDUAL of GENOTYPE aabbcc is also 1/64.The probability of producing the homozygote AABBCC is 1/64, assuming that Mendel's law of segregation is true. The probability of generating a homozygote recessive individual of genotype aabbcc is also 1/64.hope its correct .. |
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