Problems for Practice1. Calculate the % age composition of CuSO4. [Ato

1.	Problems for Practice1. Calculate the % age composition of CuSO4. [Atomic mass of Cu = 63.5, s = 32 and O 16)(Ans. Cu39.81%, S20.06%, S ;40.
Answer» Cu is 63.55H is 1.01S is 32.07O is 16.00 Next, determine how many grams of each element are present in one mole of CuSO44H2O : 63.55 g (1 mol) of Cu32.07g (1mol) of S8.08 g (8 mole x 1.01gram per mole) of H128.00 g (8 mole x 16.00 gram per mole) of O The mass of one mole of CuSO44H2O is: 63.55g +32.07g + 8.08 g +128.00g = 231.7 g The mass of the hydrate CuSO4 is63.55g + 32.07 + (4* 16.00) = 159.62g percent composition of observation 3.44/ 159.62 x 100 = 2.16% percent composition of observation from the whole hydrate 3.44 / 231.7 x 100 = 1.48% the percent composition of the hydrate CuSO4 159.62 / 231.7 x 100 = 68.89% the percent composition of water 100-68.89= 31.11 % tnx b

Problems for Practice1. Calculate the % age composition of CuSO4. [Atomic mass of Cu = 63.5, s = 32 and O 16)(Ans. Cu39.81%, S20.06%, S ;40.

Answer»

Cu is 63.55H is 1.01S is 32.07O is 16.00

Next, determine how many grams of each element are present in one mole of CuSO4*4H2O :

63.55 g (1 mol) of Cu32.07g (1mol) of S8.08 g (8 mole x 1.01gram per mole) of H128.00 g (8 mole x 16.00 gram per mole) of O

The mass of one mole of CuSO4*4H2O is:

63.55g +32.07g + 8.08 g +128.00g = 231.7 g

The mass of the hydrate CuSO4 is63.55g + 32.07 + (4* 16.00) = 159.62g

percent composition of observation

3.44/ 159.62 x 100 = 2.16%

percent composition of observation from the whole hydrate

3.44 / 231.7 x 100 = 1.48%

the percent composition of the hydrate CuSO4

159.62 / 231.7 x 100 = 68.89%

the percent composition of water

100-68.89= 31.11 %

tnx b