Process (A) : F_(2(g)) + 2e^(-) rarr 2F^(-)_((g)) , Process (B) : Cl_(2(g)) +2e^(-) rarr 2Cl_(g)^(-) which of these process is easy ? Why ?

Process (A) : F_(2(g)) + 2e^(-) rarr 2F^(-)_((g)) , Process (B) : Cl_

1.	Process (A) : F_(2(g)) + 2e^(-) rarr 2F^(-)_((g)) , Process (B) : Cl_(2(g)) +2e^(-) rarr 2Cl_(g)^(-) which of these process is easy ? Why ?
Answer» SOLUTION :`F_(2(g)) + 2e^(-) rarr 2F_((g))^(-)` is EASY. Though electron GAIN enthalpy of `Cl_((g))` to give `Cl_((g))^(-)` is more thab that of `F_((g))`to give `F_((g))^(-)` , the bond dissociation of `F_((2(g)))` is very less than that of `Cl_(2(g))`