Product of 6a2 – 7b + 5ab and 2ab is(a) 12a3b – 14ab2 + 10ab (b

1.	Product of 6a2 – 7b + 5ab and 2ab is(a) 12a3b – 14ab2 + 10ab (b) 12a3b – 14ab2 + 10a2b2(c) 6a2 – 7b + 7ab (d) 12a2b – 7ab2 + 10ab
Answer» (b) 12a³b – 14ab² + 10a²b² Now we have find product of trinomial and monomial, = (6a² – 7b + 5ab) × 2ab = (2ab × 6a²) – (2ab × 7b) + (2ab × 5ab) = 12a³b – 14ab² + 10a²b²

Product of 6a2 – 7b + 5ab and 2ab is(a) 12a3b – 14ab2 + 10ab (b) 12a3b – 14ab2 + 10a2b2(c) 6a2 – 7b + 7ab (d) 12a2b – 7ab2 + 10ab

Answer»

(b) 12a³b – 14ab² + 10a²b²

Now we have find product of trinomial and monomial,

= (6a² – 7b + 5ab) × 2ab

= (2ab × 6a²) – (2ab × 7b) + (2ab × 5ab)

= 12a³b – 14ab² + 10a²b²