Product of the following monomials 4p, – 7q3, –7pq is(a) 196 p2q4�

1.	Product of the following monomials 4p, – 7q3, –7pq is(a) 196 p2q4 (b) 196 pq4 (c) – 196 p2q4 (d) 196 p2q3
Answer» (a) 196 p²q⁴ = 4p × (– 7q³) × (–7pq) = (4 × (-7) × (-7)) × p × q³ × pq = 196p²q⁴

Product of the following monomials 4p, – 7q3, –7pq is(a) 196 p2q4 (b) 196 pq4 (c) – 196 p2q4 (d) 196 p2q3

Answer»

(a) 196 p²q⁴

= 4p × (– 7q³) × (–7pq)

= (4 × (-7) × (-7)) × p × q³ × pq

= 196p²q⁴