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Projectile motion...?

Answer» Mai seraj???????<br>Hello royal bhai kaise ho<br>Projectile MotionWhen any object is thrown from horizontal at an angle θ except 90°, then the path followed by it is called\xa0trajectory, the object is called projectile and its motion is called projectile motion.If any object is thrown with velocity u, making an angle θ, from horizontal, then\tHorizontal component of initial velocity = u cos θ.\tVertical component of initial velocity = u sin θ.\tHorizontal component of velocity (u cos θ) remains same during the whole journey as no acceleration is acting horizontally.\tVertical component of velocity (u sin θ) decreases gradually and becomes zero at highest point of the path.\tAt highest point, the velocity of the body is u cos θ in horizontal direction and the angle between the velocity and acceleration is 90°.Important Points & Formulae of Projectile Motion\tAt highest point, the linear momentum is mu cos θ and the kinetic energy is (1/2)m(u cos θ)2.\tThe horizontal displacement of the projectile after t seconds\tx = (u cos θ)t\tThe vertical displacement of the projectile after t seconds\ty = (u sin θ) t — (1/2)gt2\tEquation of the path of projectile\t\tThe path of a projectile is parabolic.\tKinetic energy at lowest point = (1/2) mu2\tLinear momentum at lowest point = mu\tAcceleration of projectile is constant throughout the motion and it acts vertically downwards being equal to g.\tAngular momentum of projectile = mu cos θ x h, where h denotes the height.\tIn case of angular projection, the angle between velocity and acceleration varies from 0° < θ < 180°.\tThe maximum height occurs when the projectile covers a horizontal distance equal to half of the horizontal range, i.e., R/2.\tWhen the maximum range of projectile is R, then its maximum height is R/4.


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