1.

Propan-1-ol can be prepared from propene by

Answer»

`H_(2)O //H_(2)SO_(4)`
`Hg(OAc)_(2)//H_(2)O` followed by `NaBH_(4)`
`B_(2)H_(6)` followed by `H_(2)O`
`CH_(3)CO_(2)H//H_(2)SO_(4)`

Solution :`6CH_(3)CH=CH_(2)+B_(2)H_(6) rarr 2(CH_(3)CH_(2)CH_(2))_(3)B UNDERSET(OH^(-))OVERSET(H_(2)O_(2))rarr 6CH_(3)CH_(2)CH_(2)OH+B(OH)_(3)`.


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