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Propylene on hydrolysis with sulphuric acid formsA. n-propyl alcoholB. isopropyl alcoholC. ethyl alcoholD. butyl alcohol |
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Answer» Correct Answer - B `underset("Propylene")(CH_(2)=CH)-CH_(3)+H_(2)Ooverset(H_(2)SO_(4))rarrunderset("isopropyl alcohol")(CH_(3)-overset(OH)overset("| ")"CH"-CH_(3))` Thus, in this reaction isopropyl alcohol is formed. |
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