1.

Propylene on hydrolysis with sulphuric acid formsA. n-propyl alcoholB. isopropyl alcoholC. ethyl alcoholD. butyl alcohol

Answer» Correct Answer - B
`underset("Propylene")(CH_(2)=CH)-CH_(3)+H_(2)Ooverset(H_(2)SO_(4))rarrunderset("isopropyl alcohol")(CH_(3)-overset(OH)overset("| ")"CH"-CH_(3))`
Thus, in this reaction isopropyl alcohol is formed.


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