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Propyne reacts with sodium in presence of liquid amonia form a compound [A]. Compound [A] reacts with a compound [B] forms 2-butyne. The compound [B] is (a) CH3 – OH (b) CH3 – Br(c) C2H5 – Br(d) CH3 – CHO |
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Answer» The compound [B] is CH3 – Br. |
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