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Prove algebraically that X + X’Y = X + Y. |
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Answer» L.H.S. = X + X’Y = X.1 + X’Y (X . 1 = X property of 0 and 1) = X(1 + Y) + X’Y (1 + Y = 1 property of 0 and 1) = X + XY + X’Y = X + Y(X + X’) = X + Y.1 (X + X’ =1 complementarity law) = X + Y (Y . 1 = Y property of 0 and 1) = R.H.S. Hence proved |
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