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Prove each of the following identities : `(cos^(3) theta + sin^(3) theta)/(cos theta + sin theta ) + (cos^(3) theta - sin^(3) theta)/(cos theta - sin theta ) = 2 ` |
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Answer» `(cos^(3)theta+sin^(3)theta)=(costheta+sintheta)(cos^(2)theta+sin^(2)theta-costhetasintheta).` And, `(cos^(3)theta-sin^(3)theta)=(cos theta-sintheta) (cos^(2)theta+sin^(2)theta+cos theta sin theta).` |
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