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Prove that:(1)P(A∪B)=P(A)+P(B)-P(A∩B)(2)P(A∪B∪C)=P(A)+P(B)+P(C)-P(A∩B)-P(B∩C)-P(C∩A)+P(A∩B∩C) |
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Answer» Prove that: (1)P(A∪B)=P(A)+P(B)-P(A∩B) (2)P(A∪B∪C)=P(A)+P(B)+P(C)-P(A∩B)-P(B∩C)-P(C∩A)+P(A∩B∩C) |
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