Saved Bookmarks
| 1. |
Prove that √3 is an irrational number. |
|
Answer» Let √3 be a rational number. Then √3 = \(\frac{q}{p}\) HCF (p,q) =1 Squaring both sides (√3)2 = (\(\frac{q}{p}\))2 3 = \(\frac{p^2}{q^2}\) 3q2 = p2 3 divides p2 » 3 divides p 3 is a factor of p Take p = 3C 3q2 = (3c)2 3q2 = 9C2 3 divides q2 » 3 divides q 3 is a factor of q Therefore 3 is a common factor of p and q It is a contradiction to our assumption that \(\frac{q}{p}\) is rational. Hence √3 is an irrational number. |
|