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Prove that 6n + 13 is an odd integer, where n is an integer. |
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Answer» To prove : 6n + 13 is odd integer , n ∈ I. Case I : When n is an odd integer n = 2m + 1 ⇒ 6n + 13 = 6 (2m + 1) + 13 = 12 m + 6 + 13 Which is odd. Case II : When n = Even = 2m 6n + 13 = 6 (2m) + 13 = 12m + 13 Which is again odd. |
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