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prove that, a^3+b^3+c^3-3abc=1/2(a+b+c)\{\lbrack a-b\rbrack+\lbrack b-c\rbrack+\lbrack c-a\rbrack\

Answer» prove that, a^3+b^3+c^3-3abc=1/2(a+b+c)\{\lbrack a-b\rbrack+\lbrack b-c\rbrack+\lbrack c-a\rbrack\


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