Prove that a+b+c=0 (a+b+c =3abc)

1.	Prove that a+b+c=0 (a+b+c =3abc)
Answer» Question is wrong.Question must be if a+b+c=0 then prove that a³+b³+c³=3abcAnsa+b+c=0a+b=-cCubing both the sides(a+b)³=(-c)³a³+b³+3ab(a+b)=-c³a³+b³+3ab(-c)=-c³a³+b³-3abc=-c³a³+b³+c³=3abc

Discussion