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Prove that: acosA + bcosB + ccosC=∆/R where a,b,c are the sides of a triangle and A,B,C are it's angles and ∆ is the area of the triangle ABC and R is the circumradius. |
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Answer» Prove that: acosA + bcosB + ccosC=∆/R where a,b,c are the sides of a triangle and A,B,C are it's angles and ∆ is the area of the triangle ABC and R is the circumradius. |
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