Prove that arctan(x) + arctan(y) = n + arctan (x+y1−xy) if x > 0, y – InterviewSolution

1.	Prove that arctan(x) + arctan(y) = n + arctan (x+y1−xy) if x > 0, y > 0 and xy > 1. And arctan(x) + arctan(y) = arctan (x+y1−xy)−n, if x < 0, y < 0 and xy > 1.
Answer» Prove that arctan(x) + arctan(y) = n + arctan $(\frac{x + y}{1 - x y})$ if x > 0, y > 0 and xy > 1. And arctan(x) + arctan(y) = arctan $(\frac{x + y}{1 - x y}) - n$ , if x < 0, y < 0 and xy > 1.

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