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prove that B-A=A\'-B\'

Answer» {tex}L.H.S.=A\'−B\'If U is universal set, then A\'=U−A and B\'=U−B⇒L.H.S.=(U−A)−(U−B)=U−A−U+B=B−A=R.H.S. (Hence Proved){/tex}


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