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Prove that distance between two parallel lines `ax+by+c_1=0` and `ax+by+c_2=0` is given by `|c_1-c_2|/(sqrt(a^2+b^2))`A. `|(c_(1)+c_(2))/(sqrt(a^(2)+b^(2)))|`B. `|(c_(1)-c_(2))/(sqrt(a^(2)+b^(2)))|`C. `|(c_(1)-c_(2))/(sqrt(a^(2)-b^(2)))|`D. `|(c_(1)-c_(2))/(sqrt(a^(2)+b^(2)))|` |
| Answer» Correct Answer - A | |