Prove that f the uncertainty in position of a moving electron is equal to its de-Brogile wavelength, then its velocity is completely uncertain

Prove that f the uncertainty in position of a moving electron is equal

1.	Prove that f the uncertainty in position of a moving electron is equal to its de-Brogile wavelength, then its velocity is completely uncertain
Answer» Solution :Here, we are given that `Delta X = lamda` By de-Brogile equation, `lamda = (h)/(p) or p = (h)/(lamda) = (h)/(Delta x) or Delta x = (h)/(p)` By uncertainty principle, `Deltax. Delta p GE (h)/(4pi) :. (h)/(p). Delta p. ge (h)/(4pi) or (Deltap)/(p) ge (1)/(4pi) or (m Deltav)/(mv) ge (1)/(4pi) or (Delta v)/(v) ge (1)/(4pi) or Delta v ge (v)/(4pi)` THUS, uncertainty in velocity is so LARGE that its velocity is UNCERTAIN