Prove that greatest integer function defined by f(x) = [x], 0<<3 is no

1.	Prove that greatest integer function defined by f(x) = [x], 0<<3 is not differentiable at x = 1
Answer» Since first not continuous at every Integral point or at x= I ⇒ It follows that [x] cannot differentiate at x = 3.

Prove that greatest integer function defined by f(x) = [x], 0<<3 is not differentiable at x = 1

Answer»

Since first not continuous at every Integral point or at x= I

⇒ It follows that [x] cannot differentiate at x = 3.

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Prove that greatest integer function defined by f(x) = [x], 0&lt;&lt;3 is not differentiable at x = 1

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Prove that greatest integer function defined by f(x) = [x], 0<<3 is not differentiable at x = 1