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Prove that (i) P(A)=P(A∩B)+P(A∩¯B) (ii) P(A∪B)=P(A∩B)+P(A∩¯B)+P(¯A∩B) |
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Answer» Prove that (i) P(A)=P(A∩B)+P(A∩¯B) (ii) P(A∪B)=P(A∩B)+P(A∩¯B)+P(¯A∩B) |
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