1.

Prove that: (i)sin(60∘−θ)cos(30∘+θ)+cos(60∘−θ)sin(30∘+θ)=1 (ii) sin(4π7+7)cos(π9+7)−cos(4π9+7)sin(π9+7)=√32 (iii)sin(3π8−5)cos(π8+5)+cos(3π8−5)sin(π8+5)=1

Answer»

Prove that:
(i)sin(60θ)cos(30+θ)+cos(60θ)sin(30+θ)=1
(ii) sin(4π7+7)cos(π9+7)cos(4π9+7)sin(π9+7)=32
(iii)sin(3π85)cos(π8+5)+cos(3π85)sin(π8+5)=1




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