1.

Prove that: (i) sin θ cos (90∘−θ)+sin(90∘−θ)cos θ=1 (ii) sin θcos (90∘−θ)+cos θsin (90∘−θ)=2 (iii) sin θ cos(90∘−θ)cos θsin (90∘−θ)+cos θ sin (90∘−θ)sin θcos (90∘−θ)=1 (iv) cos(90∘−θ)sec(90∘−θ)tan θcosec(90∘−θ)sin(90∘−θ)cot(90∘−θ)+tan(90∘−θ)cot θ=2 (v) cos(90∘−θ)1+sin(90∘−θ)+1+sin(90∘−θ)cos(90∘−θ)=2cosec θ (vi) sec(90∘−θ)cosec θ−tan(90∘−θ)cot θ+cos225∘+cos265∘3 tan 27∘ tan 63∘=23 (vii) cot θ tan(90∘−θ)−sec(90∘−θ)cosec θ+√3 tan 12∘ tan 60∘ tan 78∘=2

Answer»

Prove that:

(i) sin θ cos (90∘−θ)+sin(90∘−θ)cos θ=1

(ii) sin θcos (90∘−θ)+cos θsin (90∘−θ)=2

(iii) sin θ cos(90∘−θ)cos θsin (90∘−θ)+cos θ sin (90∘−θ)sin θcos (90∘−θ)=1

(iv) cos(90∘−θ)sec(90∘−θ)tan θcosec(90∘−θ)sin(90∘−θ)cot(90∘−θ)+tan(90∘−θ)cot θ=2

(v) cos(90∘−θ)1+sin(90∘−θ)+1+sin(90∘−θ)cos(90∘−θ)=2cosec θ

(vi) sec(90∘−θ)cosec θ−tan(90∘−θ)cot θ+cos225∘+cos265∘3 tan 27∘ tan 63∘=23

(vii) cot θ tan(90∘−θ)−sec(90∘−θ)cosec θ+√3 tan 12∘ tan 60∘ tan 78∘=2



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