1.

Prove that :(i) tan 20° tan 35° tan 45° tan 55° tan 70° = 1(ii) sin 48° sec 42° + cos 48° cosec 42° = 2(iii) sin 70°cos 20°+cosec 20°sec 70°-2 cos 70° cosec 20°=0(iv) cos 80°sin 10°+cos 59° cosec 31°=2

Answer» Prove that :



(i) tan 20° tan 35° tan 45° tan 55° tan 70° = 1

(ii) sin 48° sec 42° + cos 48° cosec 42° = 2

(iii) sin 70°cos 20°+cosec 20°sec 70°-2 cos 70° cosec 20°=0

(iv) cos 80°sin 10°+cos 59° cosec 31°=2


Discussion

No Comment Found

Related InterviewSolutions