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Prove that :(i) tan 20° tan 35° tan 45° tan 55° tan 70° = 1(ii) sin 48° sec 42° + cos 48° cosec 42° = 2(iii) sin 70°cos 20°+cosec 20°sec 70°-2 cos 70° cosec 20°=0(iv) cos 80°sin 10°+cos 59° cosec 31°=2 |
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Answer» Prove that : (i) tan 20° tan 35° tan 45° tan 55° tan 70° = 1 (ii) sin 48° sec 42° + cos 48° cosec 42° = 2 (iii) (iv) |
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