1.

Prove that if for an exponential function y=a^x (a gt 0, a ne 1) the values of the argument x=x_n (n=1,2,.....) form an arithmetic progression,then the corresponding values of the function y_n=a^(x) (n=1,2,3..) form a geometric progression.

Answer»


ANSWER :From `x_(N+1)=x_(n)+d` it FOLLOWS that `y+(n+1)=a^(x_(n+1))=a^(XN+d)=a^(xn) a^(d)`


Discussion

No Comment Found

Related InterviewSolutions