Prove that if `p=2-a` , then `a^3+6ap+p^3-8=0` – InterviewSolution

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1.	Prove that if `p=2-a` , then `a^3+6ap+p^3-8=0`
Answer» P=a `a^3+6ap+p^3-8=0` LHS `a^3+6ap+p^3-8` `a^3+6a(2-a)+(2-a)^3-8` `a^3+6a*2-a)+8-a^3-6a(2-a)-8` ``0` RHS.

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