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Prove that in a quadrilateral the sum of all the sides is greater than the sum of its diagonals. |
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Answer» Given: Let ABCD is a quadrilateral with AC and BD as its diagonals To Prove: Sum of all the sides of a quadrilateral is greater than the sum of its diagonals Proof: Consider a quadrilateral ABCD where AC and BD are the diagonals AB+BC > AC (i) (Sum of two sides is greater than the third side) AD+DC > AC (ii) AB+AD > BD (iii) DC+BC > BD (iv) Adding (i), (ii), (iii), and (iv) AB+BC+AD+DC+AB+AD+DC+BC > AC+AC+BD+BD 2(AB+BC+CD+DA) > 2(AC+BD) AB+BC+CD+DA > AC+BC Hence, proved that the Sum of all the sides of a quadrilateral is greater than the sum of its diagonals |
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