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In figure AB = AC and D is mid point of BC.(i) Write three pairs of equal parts in ∆ADB and ∆ACD.(ii) Is ∆ADB = ∆ADC ?Give reason.(iii) What is relation between ∠B and ∠C? |
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Answer» (i) In ∆ADB and ∆ADC AD = AD (common) AB = AC (given) and DB = DC (∵ D is mid point of BD) (ii) By S.S.S. rule of congruency. ∆ADB ≅ ∆ADC (iii) ∠B = ∠C (CPCT) |
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