1.

In figure AB = AC and D is mid point of BC.(i) Write three pairs of equal parts in ∆ADB and ∆ACD.(ii) Is ∆ADB = ∆ADC ?Give reason.(iii) What is relation between ∠B and ∠C?

Answer»

(i) In ∆ADB and ∆ADC

AD = AD (common)

AB = AC (given)

and DB = DC (∵ D is mid point of BD)

(ii) By S.S.S. rule of congruency.

∆ADB ≅ ∆ADC

(iii) ∠B = ∠C (CPCT)



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