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Prove that in series combination of electrical appliances, the reciprocal of total power consumption is equal to the sum of the reciprocal of the powers of the individual appliances. |
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Answer» Let `P_(1),P_(2),P_(3)` be the powers of electrical appliances at V volt. If `R_(1), R_(2), R_(3)` are their resistance, then `R_(1)=V^(2)/P_(1), R_(2) = V^(2)/P_(2) and R_(3) = V^(2)/P_(3)` When the electrical appliances are connected in series, then effective resistance, R is `R = R_(1) + R_(2) +R_(2)` or `R/V^(2) = R_(1)/V^(2) + R_(2)/V^(2) + R_(3)/V^(2)` or `1/(V^(2)//R) = 1/(V^(2)//R_(1)) + 1/(V^(2)//R_(2)) + 1/(V^(2)//R_(3))` or `1/P = 1/P_(1) + 1/P_(2) + 1/P_(3)` |
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