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Prove that,logab abclobe abc log.ca abe |
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Answer» 1/logab[abc] +1/logbc[abc] +1/logca[abc] = logab/log[abc] + logbc/log[abc] + logca/log[abc] = log(ab*bc*ca)/log[abc]= log(abc)²/log[abc]= 2. |
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