Prove that (n!).(n+2)=[(n!)+(n+1)!]

1.	Prove that (n!).(n+2)=[(n!)+(n+1)!]
Answer» RHS, [(n!) +(n+1)!] =(n!) +(n+1).(n!) =(n!). (1+n+1) (on taking common) =(n!). (n+2)LHS, (n!). (n+2)Therefore, RHS=LHS

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