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Prove that S=at + 1/2at^2

Answer» (First draw the diagram. Here the link to it below) https://pin.it/1fSSKZaAO= u (initial velocity) BC= v (finial velocity)CO= t (time) BD= BC-DC = v-u S= area under the graph (which is the trapezium AOCB or the Rectangle AOCD + ∆ABD) (Area of rectangle is L x B and area of triangle is 1/2 x base x height) S= area of rectangle AOCD + area of ∆ABDS= OA x OC + 1/2 x t x v-uS= u x t + 1/2 x t x (v-u) (From equation 1- v=u + at v-u=at) Put the value of (v-u) from equation 1.S= ut+1/2 x t x atS= ut+1/2 x at²S=ut + 1/2 at²Hence, proved


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