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| 1. |
Prove that sin^2(18)^@ + cos^2(36)^@ = 3/4 |
| Answer» SOLUTION :`sin^2 18^@+cos^236^@=`((sqrt5-1)/4)^2+((sqrt5+1)/4)^2=((sqrt5-1)^2+(sqrt5+1))/16=3/4` | |