1.

Prove that tan−1(6x−8x31−12x2)−tan−1(4x1−4x2)=tan−12x;|2x|<1√3.

Answer» Prove that
tan−1(6x−8x31−12x2)−tan−1(4x1−4x2)=tan−12x;|2x|<1√3.


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