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Prove that the angles opposite to equal sides of an isosceles triangle are equal

Answer» Given: A triangle ABC in which AB = ACTo Prove: ∠ABC = ∠ACBConstruction: Draw the bisector AD of A so as to intersect BC at D.Proof: In ∆ADB and ∆ADC,AD = AD | CommonAB = AC | Given∠BAD = ∠CAD| By Construction∴ ∆ADB ≅ ∆ADC | SAS congruence rule∴ ∠ABD = ∠ACD | CPCT⇒ ∠ABC = ∠ACB


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