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Prove that the area of the parallelogram formed by the lines 3x−4y+a=0, 3x−4y+3a=0, 4x−3y−a=0 and 4x−3y−2a=0 is 2a27 sq. units. |
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Answer» Prove that the area of the parallelogram formed by the lines 3x−4y+a=0, 3x−4y+3a=0, 4x−3y−a=0 and 4x−3y−2a=0 is 2a27 sq. units. |
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