Prove that the centres of the three circles x2+y2−4x−6y—−12=0, – InterviewSolution

1.	Prove that the centres of the three circles x2+y2−4x−6y—−12=0,x2+y2+2x+4y−10=0 and x2+y2−10x−16y−1=0 are collinear.
Answer» Prove that the centres of the three circles $x^{2} + y^{2} - 4 x - 6 y — - 12 = 0, x^{2} + y^{2} + 2 x + 4 y - 10 = 0$ and $x^{2} + y^{2} - 10 x - 16 y - 1 = 0$ are collinear.

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