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Prove that the difference of a number and its reciprocal will be always positive. |
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Answer» Number = x, its reciprocal = 1/x then, x − \(\frac{1}{x}\) = k \(x^2-kx-1=0,x=\frac{+k\,\pm \sqrt{k^2+\,4} }{2}\) Since k being a positive number, k2 + 4 also negative. |
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