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Prove that the following. [[a+d,a+d+k,a+d+c],[c,c+b,c],[d,d+k,d+c]]=abc |
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Answer» SOLUTION :`[[a+d,a+d+K,a+d+C],[c,c+B,c],[d,d+k,d+c]]` `[[a,a,a],[c,c+b,c],[d,d+k,d+c]] (R_1~~R_1-R_3)` `a[[1,1,1],[c,c+b,c],[d,d+k,d+c]]` `a[[1,0,0],[c,b,-b],[d,k,c-k]]` `(C_2=C_2-C_1,C_3=C_3-C_2)` `a[[b,-b],[k,c-k]]` =a(-bk+bc+bk)=ABC |
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