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Prove that the function f given by f(x) = x3 – 3x2 + 4x is strictly increasing on R ? |
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Answer» Given, f(x) = x3 - 3x2 + 4x \(\therefore\) 3x2 - 6x + 4 = 3(x2 - 2x + 1) + 1 = 3(x - 1)2 + 1 > 0 for all x ∈ R Hence f(x) is strickly increasing on R |
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