Prove that the ionisation energy of hydrogen atom is 13.6 eV. – InterviewSolution

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1.	Prove that the ionisation energy of hydrogen atom is 13.6 eV.
Answer» n=1 corresponds to ground state. `E=(-13.6)/(n^(2))eV` `E=(-13.6)/(1^(2))eV` `E=-13.6 eV` `therefore` The minimum energy required to free the electron from the ground state of hydrogen atom =13.6 eV. `therefore` Ionisation energy of hydrogen atom = 13.6 eV.

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