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Prove that the kinetic energy of a freely falling object on reaching the ground is nothing but the transformation of its initial potential energy. pls give answer . I have to sleep |
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Answer» Total ENERGY at initial position = K.E + P.E = 0 + mghTotal energy when it REACHES the ground = K.E + P.E = 0.5mv^2 + 0VELOCITY when it reaches the ground = sqrt(2gh)Substitute velocity in total energy equationTotal energy when it reaches the ground = 0.5mv^2 = 0.5m * 2gh = mghWe found that total energy when it reaches the ground = Total energy at initial position.In other words, KINETIC energy with which it hits the ground is the transformation of its initial potential energy.Ok nancy you can SLEEP now bye |
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