Prove that the path of a projectile is parabola

1.	Prove that the path of a projectile is parabola
Answer» Let a body is projected with speed u m/s inclined θ with horizontal line .Then, vertical component of u, = ucosθHorizontal component of u , = usinθacceleration on horizontal, ax = 0acceleration on vertical, ay = -gNow, use formula ,x =\xa0x = ucosθ.tt = x/ucosθ------(1)Again, y =\xa0y = usinθt - 1/2gt²Put equation (1) here,y = usinθ × x/ucosθ - 1/2g × x²/u²cos²θ= tanθx - 1/2gx²/u²cos²θThis equation is similar to Standard equation of parabola y = ax² + bx + c her, a, b and c are constantSo, A projectile motion is parabolic motion

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