Prove that the perpendicular bisector of the hypotenuse of 30∘−60� – InterviewSolution

1.	Prove that the perpendicular bisector of the hypotenuse of 30∘−60∘−90∘ triangle divides the larger leg into two parts having the ratio 2:1.
Answer» Prove that the perpendicular bisector of the hypotenuse of $30^{\circ} - 60^{\circ} - 90^{\circ}$ triangle divides the larger leg into two parts having the ratio 2:1.

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