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Prove that the pressure of an ideal gas is numerically equal to two third of the mean translational kinetic energy per unit volume of the gas. |
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Answer» Translational `kE` per unit volume `E=(1)/(2)` ( mass perunit volume) `(v^(2))=(1)/(2)(p)((3p)/(p)=(3)/(2)p)` `or" " p=(2)/(3)E` |
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