InterviewSolution
Saved Bookmarks
| 1. |
Prove that the sum of the vectors represented by the sides of a closed polygon taken in order is a zero vector. |
Answer» Solution : Then by triangle law `VEC(AB)+vec(BC) = vec(AC), vec(AC)+vec(CD) = vec(AD)` `vec(AD)+vec(DE) = vec(AE), vec(EF)+vec(FA) = vec(EA)` ADDING the above RELATIONS we get `vec(AB)+vec(BC)+vec(AC)+vec(CD)+vec(AD)+vec(DE)+vec(EF)+vec(FA) = vec(AC)+vec(AD)+vec(AE)+vec(EA)` `implies vec(AB)+vec(BC)+vec(CD)+vec(DE)+vec(EF)+vec(FA)` =`vec(AE)+vec(EA) = 0` |
|