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Prove that time taken by a body to rise to highest point is always equal to the time taken by it to fall through he same height. |
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Answer» (i) Time taken by body to rise to highes point from `v=v+at` `0=u-g t, t=(u)/(g)` From `v^(2)-u(2)=2as` `0-u^(2)=(-g)h,h=u^(2)/2g` this is the maximum height. (ii) time taken by the bnody to fall to ground From `s=ut+(1)/(2)at^(2)` `u^(2)/2g=0+(1)/(2)g t^(2)` `r^(2)=u^(2)/g^(2),t=(u)/(g)` which is same as in (i) above. |
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