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Prove that two angle sum of a quadrilateral is 360 |
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Answer» All are 90 degree so they are 4 90+90+90+90 360 Consider a quadrilateral PQRS. Join QS.To prove: ∠P + ∠Q + ∠R + ∠S = 360ºProof: Consider triangle PQS, we have,⇒ ∠P + ∠PQS + ∠PSQ = 180º ... (1) [Using Angle sum property of Triangle]Similarly, in triangle QRS, we have,⇒ ∠SQR + ∠R + ∠QSR = 180º ... (2) [Using Angle sum property of Triangle]On adding (1) and (2), we get∠P + ∠PQS + ∠PSQ + ∠SQR + ∠R + ∠QSR = 180º + 180º⇒ ∠P + ∠PQS + ∠SQR + ∠R + ∠QSR + ∠PSQ = 360º⇒ ∠P + ∠Q + ∠R + ∠S = 360º [Hence proved] ?????⏳⌛⏰♏♎♍♌♋♊♉♈♐♑♒♓⛎??????????????????➿♿???????♻??⚠??⛔?????????????????⭕㊗??㊙???❌❎ℹ?✅✔?✴???➗✖➖➕✳?????????????????????????↕⬆?????↗➡↘⬇↙⬅↖↔▶◀⏩⏬⏫⏪⤵⤴??❇✨??⚪⚫◾◽▫??⭐??◻◼⬜⬛????〰⁉❗❕❓❔??➰♠♥♣♦??↩?☑?↪??????????????????? |
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